澳洲计算机IT 编程assignment 代写

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  • 澳洲计算机IT 编程assignment 代写
    Header file:
    #include <stdio.h>
    #include <stdlib.h>
    #include <math.h>
    #include <float.h>
    #include <malloc.h>
    #include "q2_header.h"
     
    void DFT(double *x, double *y,int N)
    {
             double **CNI;
             CNI=makeCNI(N);
             complexMatrixVectorMultiply(CNI,y,N,N,x);
    }
    void FastDFT(double *x,double *y,double *w,double *Wp,int N,int skip);
     
    FastDFT file:
    void FastDFT(double *x,double *y,double *w,double *Wp,int N,int skip)
    {
        int i,j;
        if (N==1)
        {
                 memcpy(x,y,2*sizeof(double));
        }
        else if (N % 2 && N!=1)
        {
            DFT(x,y,N);
        }
        else
        {
                 /*place xe and xo in w,from head to tail.*/
            for (i=0;i<N;i=i+2)
            {
                     memcpy(w+i,x+2*i,2*sizeof(double));
            }
     
            for (i=0;i<N;i=i+2)
            {
                     memcpy(w+(i+N),x+(2*i+2),2*sizeof(double));
            }
     
            FastDFT(w,y,x,Wp,N/2,skip*2);//the even half of y, i.e., ye
            FastDFT(w+N,y+N,x+N,Wp,N/2,skip*2);//the odd half of y, i.e., yo
     
            memcpy(w,y,sizeof(double)*2*N);//copy the value of ye,yo into w.
            for(j=0;j<N;j+=2)
            {
                     double temp[2]={0,0};
                     double times[2]={N,0};
                     complexMultiply(&Wp[2*N-j],&w[j+N],&temp);
                     complexMultiply(&temp,&times,&temp);
                     complexAdd(&w[j],&temp,&y[j]);
                     complexMultiply(&Wp[N-j],&w[j+N],&temp);
                     complexMultiply(&temp,&times,&temp);
                     complexAdd(&w[j],&temp,&y[j+N]);
            }
        }
    }
    澳洲计算机IT 编程assignment 代写
    F+C2=2, F*C2=2, F+R2=8, F*R2=8
    If F+CN, F*CN,F+RN,F*RN are known, then
    F+C2N=2*F+CN+2*N,
    F*C2N=2*F*CN+2*N,
    F+R2N=2*F+RN+8*N,
    F*R2N=2*F*RN+8*N
    The values of these 4 numbers from N=2 up to N=220 could be calculated using Excel, and the results are represented as below:

    Since F+C2N=2*F+CN+2*N, it is clear that F+C2N=2N*F+C1+2*N*log22N,
    and since F+C1=0, F+C2N=2*N*log22N,
    Hence, F+CN=N*log2N.
    Similarly, it could be proved that F*CN=N*log2N, F+RN=4*N*log2N, and F*RN=4*N*log2N.
     
    澳洲计算机IT 编程assignment 代写
    According to some tests, the FastDFS function is twice as fast as a direct matrix-vector multiply when N is 2, as shown below:

    The FastDFS function is twice as fast as a direct matrix-vector multiply when N is 16, as shown below: